5x^2-62x+24=0

Solution for 5x^2-62x+24=0 equation:

5x^2-62x+24=0

a = 5; b = -62; c = +24;
Δ = b2-4ac
Δ = -622-4·5·24
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-58}{2*5}=\frac{4}{10}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+58}{2*5}=\frac{120}{10}
=12
$